is there a convergent series which has a limit of 100
Is there a convergent series which has a limit of 100
Colton Campbell
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Austin Price
No sadly
Jonathan Phillips
[math] x(n)=\sum_{k=1}^n 9\cdot 10^{2-k} [/math]
Lucas Howard
Take your favourite convergent series and multiply every term by 100 divided by the original limit of that series.
Parker Miller
[math]x(n)=100[/math]
Dominic Davis
wow holy shit BTFO
Caleb Campbell
What if my favourite convergent series is
[eqn] \sum_{k=0}^\infty \left( \frac{k+1}{k^2 + 2k + 2} - \frac{k}{k^2 + 1} \right) [/eqn]
?
Jonathan Torres
[math]\sum_{k=0}^\infty 100\left( \frac{\frac{k+1}{k^2 + 2k + 2} - \frac{k}{k^2 + 1}}{ \sum_{k=0}^\infty \left( \frac{k+1}{k^2 + 2k + 2} - \frac{k}{k^2 + 1} \right)}\right)[/math]
Jace Jenkins
God damn it
Jonathan Nelson
[eqn] \frac{600}{\pi^2} \sum_{n=1}^\infty \frac{1}{n^2} [/eqn]