Do your own homework, high schooler.
Do your own homework, high schooler
5e11
2^1000000
oh, you need the sum
2^1000000 - 1
wait this is wrong, ignore my answer
166667166667000000
166667166667000000
C'mon sci this is just arithmetic progression
0.5n(n+1) where n is 1000000
>bases his answer on a misleading drawing instead of reading attentively
F
retard
...
[math]\sum_{n=1}^{1000000}\sum_{k=1}^{n}k = \sum_{n=1}^{1000000}\frac{n(n+1)}{2}
=\frac{1}{2}\sum_{n=1}^{1000000}n^2 + \frac{1}{2}\sum_{n=1}^{1000000}n[/math]
[math]=\frac{1}{2}*\frac{1000000(1000000+1)}{2} + \frac{1}{2}*\frac{1000000(1000000+1)(2*1000000+1)}{6} [/math]
[math]=250000250000 + 166666916666750000 = 166667166667000000[/math]
There you go, OP
500000500000 ?
pls no bully
...
If you want them regular, then 6 plus few spare parts
Well then it's the sum of arithmetic prog.
sum from n=1 to m of 0.5n(n+1) = 1/6m(m+1)(m+2)
so your answer is 1/6m(m+1)(m+2) where m = 1000000 then it equals 166 667 166 667 000 000
Intentionally misleading drawings and graphs are cancer
i think this is correct
1.000.001*500.000
noticed this is 3D not 2D
Fuck brainlet after all
>Intentionally misleading drawings and graphs are cancer
The picture explained the problem very clearly, stop lashing out just because you were retarded.
You know damn well what I meant pretentious faggot
No, I seriously don't understand what's the problem. Drawing actual tetrahedral images to explain the idea behind the problem would have made the image cluttered and more confusing if anything. Explaining it with layers was perfectly clear and hardly misleading, unless you didn't bother to read through two whole paragraphs of text.