What's the answer?

Not necessarily. It could be a problem about finite rings of integers.

Can it be solved using wheels?

O = 8

8 doesn't necessarily have to equal 8

If 1=2, then 2*1=2*2. Doing the operation again we get 2*2*1=2*2*2. In other words, 4=8. Since equality is commutative, 8=4. We know that 8=O, so it must be that O=4.

Wrong

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Let me try again. We know 0=6 and 1=2. It is well known that 8=2+6 (proof left to the reader). Replacing 2 and 6 by their 'alternative' values, we get 8=1+6 or 8=2+0 or 8=1+0. Therefore, 8 equals 1, 2 or 7. It cannot equal 1 because we know that's equal to 2 (of course). It cannot be 2 because we know that's equal to 1.

Conclusion: 8=7.

Wrong.

8=3