Let's see these "geniuses" in here solve this one

Let's see these "geniuses" in here solve this one

18-2x3+4 = ?

Only top-tier math operators can solve this one.

18 - ((2 x 3) + 4)
18 - (6 + 4)
18 - 10
8

[math]18 - 2x3 + 4\\
18 - 6x + 4\\
22 - 6x[/math]

wrong

fuck off drumpft

by "x"
do you mean * as in multiplication or X as in a variable or constant?

18-2*3+4
= 18-(2*3-4)
= 18-(6-4)
= 18-2
= 15

straight out of 1984

= 18-2
= 15
BAHAHAHAHAHAHAHAHAHAHAHAAHAHAHAHAHAHAHAHAHAHAHAHAHAHAHAHAHAHAHAHAHAHAHAHAHAHAHAHAHAHAHAHAH

In what wheel?

16

Yes

I know that it can happen to anyone but still...

Sorry, tried, guess I'm not stable enough.

>linear operation
>ambiguous operating sign
>?
>no brackets
Let's see if "genius" OP can formulate a proper grade 6 mathematical problem first.

>18-2x3+4 =
18-6+4 =
12+4 = 16

I got indeterminate

? = 16, Mr. president.

Write it in postfix notation and it will be unarguably solved.

18 minus 2 times 3 that's 12
add 4 get 16 quick math

>[math]x[/math]
>not [math]\times[/math]

If you're gonna [math]\LaTeX[/math], at least do it properly.

>I got indeterminate
Only correct answer.
left to right is a convention followed by some (but not all) programming languages, but is not part of PEDMAS, according to the nuns at Sacred Heart.

=(2*9)+(-2*3)+(2^2)
=(2^1 * 3^2 + 2^2) + (-6)
=(6^2+ 2^2) -6
=8^4 - (6^1)
=2^3
=8

18-2x3+4
16x3+4
48+4
52

18-2x3+4=
18-6+4=
12+4=
16.

As has been stated in other threads, you use the order if operations then you solve fro mn left to right if thier is any remaing ambiguity.

18-2x3+4=
16x3+4=
48+4=
52

If by "x" you mean '*,' the answer is eight.
If x is an unknown variable, then its 11/3.