This should take you 10 seconds max to figure out

21.46

>actual homework
>10 replies

It doesn't make a difference at all, it's just something teachers do to force their students to practice factoring for when it does become relevant.

Find length AB

((10*20) - ((pi*5^2)*2))/2 = 21.46

The fact that you thought this was difficult enough to warrant a thread on Veeky Forums means you are too stupid to be here. Please leave.

(1/3)OE

Not enough information. We cant be sure the circles are all of equal size because they aren’t labeled as such.

Also AB isn't the diameter

Also, those aren't circles. Also that's not a rectangle. Also that's not a diagonal. Also we're not in Euclidean space.

"hard"

0.3258OE.

[math]\frac{ A_{rec}-2A_{circ}}{2}\,\,\,A_{rec}=200\,\,\,A_{circ}=25\pi [/math]

>it's looks it so it must be it
>durrrr

>durr why check the second thing?

25

10*20*0.5 - pi*25 = 100 - pi*25

Graphs of continuous functions have measure zero, baka

Prove that the combined circle area under the diagonal equals the combined circle area above the diagonal

It's not homework, it's a test question given to chinese students. We've seen it before which is why the answers come so fast.

youtube.com/watch?v=xnE_sO7PbBs

that's just like proving the bottom triangle has he same area as the top triangle
>trivial

I've never seen it and I got the answer immediately, it's very obvious.

>if it's so trivial blah blah...

g-g-guys... WHAT HAPPENED to the bottom left red spot!?!?

tanh(20)

>OP is a chinese student.

bh/2
b t f o

GodDAMNIT, user!

Start with full area: 10 * 2(10) = 200

Subtract area of circles: 200 - (2 * (5^2 * pi)) ~= 42.92

Divide by two -> 21.46

10^2-pi*5^2 = 100(1-1/4pi)

Mathematical beauty