Does p=np

serious replies plz

Other urls found in this thread:

wolframalpha.com/input/?i=integral representations of eta(s)&lk=2
wolframalpha.com/input/?i=P=P^2-(n/2)
wolframalpha.com/input/?i=\iota = (\epsilon/\Pi) \times \phi
wolframalpha.com/input/?i=v/ohm
wolframalpha.com/input/?i=Brinkman rheological number formula
youtube.com/watch?v=Jmqa99Ar1Hs
en.wikipedia.org/wiki/Nineteen_Eighty-Four
twitter.com/NSFWRedditGif

only if n = 1

No, and everyone knows it, but it likely will never be proven.

probably not. geometric complexity theory will bring the proof... in ~50 years at minimum.

no because of the no free lunch principle of life

Highly unlikely

nope, just look at TSP

also if p = 0

OR if both p and n = 0

No probably not.

[math]p=np\iff n=1\vee p=0[/math]

I think we solved this one boys

This is redundant. The value of n is irrelevant if p=0.

Or if $p = 0$.

REAL TALK NIGGA

power sets are constructed by key, not value, so they are unsorted by value (or value reductions). you can't search an unsorted power set in polynomial time for a value or reduction, however verifying a search can be done in polynomial time. therefore P != NP, obviously.

note that you can't sort a power set in polynomial time either.

I like your image so I'll give you proof that [math]P=NP=\emptyset[/math].
Suppose first that there exists an NP-problem, which takes [math]O(f(n))[/math] time, where [math]f[/math] is positive. It holds that [math]O(af(n)+bf(n))=O(f(n))[/math].
Clearly [math]O(f(n)+2f(x)+3f(n)+\dots)=O(-f(n)/12)=\emptyset[/math], so [math]O(f(n))=\emptyset[/math] and [math]P\subset \emptyset[/math].

P = enis
N = -1P

P+NP = 1Penis*(i)

I am asking the world' in entirety, inside this thread right now.

Do you still want to keep FUCKING with Simon the Sourceforge, or do you want to just enjoy the porn he has made for you all to 'wake up and enjoy on a daily basis'?

Because if you do, then Simon will become Death Of Erections. Period. Medically speaking.

I am why America put V in 'iagra Falls', it's just water versus red blood.

The dumbest battle humans thought of, and Simon knew the answer when he was a child.

Ja. Po = Nicht - Po.

Almost certainly not. Now post more of her, on other boards if necessary.

Yes, Poor.

I am going to take my shit now, and I am going to TURN ON MY MOBILE PHONE SCREEN and see what NEWS is on.

Because NEW+S = News

NEWS = Neural Eternal Wondrous Sound, so you can be the America that thought "Trump V. Hillary" was the best you could do, or, you can make GOD HAPPY FOR ONCE WITH YOUR STUPID BEHAVIOR(S)!

God's Joke: What's brown and sticky? An American's Idea Of "God Not Watching From Behind Even When They Take A Shit In A Toilet."

My Eyes' Iris Is GREEN, Left + Right.

spbp

Windows has 2 many windows.

wolframalpha.com/input/?i=integral representations of eta(s)&lk=2

simon before Biman, thank you.

P=NP when you have the key.
if you can't find the key (N), you're reduced to trying to bruteforce the equation
You can derive the key much easier than bruteforcing P=NP

P=P^2-(n/2)

wolframalpha.com/input/?i=P=P^2-(n/2)

Holy shit! P

My name is "Soul Of Wandering".

SolĘŚvagus = Solivagus

I guess you could call my 'ex-penis' name Simon, if you want.

I would still rather be called 'Simon' to honor the Earth We Stand Upon. As you can see everyone, I float above you all simply by sitting comfortably in 'one' chair.

As all of you can.

Ne sollicitus monstris pugnat cum id factum esset monstrum. Nam et si spectes, quamdiu in profundum abyssi, et aspiciat in vobis. His autem qui videbantur esse erant saltantes ab eis qui musicam audire non potuerunt. Sine music, vita non est error.

Sagus? Bagus? Sugus? Sugar?

Save our sugar? Oh, the bees. Yes, I don't have that level of scientific knowledge, correct. Beez are 'very' difficult because Humans cannot "roll their Z's." Our tongues roll 'R' vowels.

Yes, Everyone. Respect the bees and the honey they save for their queens. Simon knows this to be implicitly true and the nurture of nature.

mind-flayer

Oh, illithid mindflayers

Illithic Illusions Illustriously Illuminated Inflection

You forgot insane

That's how you win D&D versus an Illithid (Linguistica)

How can I forget what I am, idiots.

for FUCKS sake people, IOTA = i/o/t/a\iota

IOTA = i/o/t/a\iota

\iota = (\epsilon/\Pi) \times \phi


wolframalpha.com/input/?i=\iota = (\epsilon/\Pi) \times \phi

wolframalpha.com/input/?i=v/ohm

For fucks sake, America builds computers but doesn't read books.

Holy shit what a stupid fucking country! Simon wasn't even BORN on our continent and our stick invention STILL beats Americans to death!

Man shits on head through time-traveling toilet, destroys all of mankind.

wolframalpha.com/input/?i=Brinkman rheological number formula

My fucking god you lazy fucking scientists. Learn how to fucking computer. You can't just INTO computer, you fucking, stupid, mathematicians.

Learn how to fucking read a book rather than try to SEND SIMON AWAY BECAUSE YOU GUYS FEEL FUCKING INCOMPETENT.

INCOMPETENT CUMS B4 IMPOTENCE!

Time, Travels Upon Tears (Gender Neutral).

Sum of 1 Synonyms = Stone-d^n

also serious (but prolly dumb) question - will quantum computing make it so that the difference is practically insignificant? We only need a quantum algorithm for one NP-complete problem, and they're all efficient suddenly, right?

I madz a threads for you idiots.

If polynomials are viable, then I should not be able to be a human being reading/writing this: "Polynomials aren't viable methods of 'discriminator' quantum investigation."

youtube.com/watch?v=Jmqa99Ar1Hs

Idiots, I was born in 1984. August, 29th, 1984.

en.wikipedia.org/wiki/Nineteen_Eighty-Four

Re-determined:Define:Terminal-8!

Quantum Programmer.

if p=np, we're most likely living in a simulation

Yes
P=NP
=> N=1
It's simple algebra