Is anybody in here smart enough to solve this?

TreeEater
TreeEater

Is anybody in here smart enough to solve this?

Attached: IMG-6621.jpg (8 KB, 470x277)

VisualMaster
VisualMaster

I'm assuming y' is d(y)/dy. Nonetheless, you have 2 unknowns and 1 equation. This cannot be solved without another given linearly independent equation.

eGremlin
eGremlin

y=2, t=1.

Any other questions?

GoogleCat
GoogleCat

LOL

idontknow
idontknow

y=1, t=2 is obviously the only correct answer

fuck you

Attached: Screenshot-from-2018-02-25-16-50-30.png (16 KB, 1112x216)

Methnerd
Methnerd

differential equations
what are you, a college junior?

Carnalpleasure
Carnalpleasure

You are.

I believe in you OP

Sharpcharm
Sharpcharm

solution is y(t) = c_1 e^(-t^2) + 2 sqrt(π) e^(-t^2) erfi(t)
btw.
pls don't make yourself look retarded and ask me what erfi is

Flameblow
Flameblow

y' = 4 - 2ty
y = 4y + ty^2
1 = 4 + ty
-3 = ty
t = -3/y

y' + 2ty = 4
4 - 2ty + 2ty = 4

4 - 2y(-3/y) + 2y(-3/y) = 4

-2y(-3/y) + 2y(-3/y) = 0

6 - 6 = 0

what do i win

RumChicken
RumChicken

Wow it's almost like t is a variable not any random constant you make up

I'm actually a freshman LOL I'm super smart though I took AP calc in high school and got a 3 on the test

FastChef
FastChef

I'm super smart
lol
anyone who says this unironically is 100% a fucking brainlet

CodeBuns
CodeBuns

I'm super smart
sure buddy
got a 3
3 on what scale

Spazyfool
Spazyfool

then pls tell us what the correct solution was, it's already been posted here.
Let's see who the brainlet is

Garbage Can Lid
Garbage Can Lid

AP exams are scored out of 5. 3 is literally brainlet tier.

Crazy_Nice
Crazy_Nice

it's out of 5, 3 is just under 50%

farquit
farquit

being this much of a brainlet

5mileys
5mileys

I hate this way of writing. If y is a function, and t is the variable, you should write
[math]\forall t, 3y'(t) + 6ty(t) = 12[/math]

You wouldn't have stupid answers as

But somehow mathematicians find this rigorous...

SniperGod
SniperGod

percentile

TechHater
TechHater

First order linear ODE?
I could do that in high school.
Integrating factors are for babies.

BunnyJinx
BunnyJinx

Then apologies, my gentleman

whereismyname
whereismyname

no, anyone who knows differential equations would know what OP means. they are just retarded highschoolers who try to look smart.

Illusionz
Illusionz

yes there are many of us

Need_TLC
Need_TLC

3 unknowns* (also y'). Also needs an initial condition (another lin indep equation).

Lord_Tryzalot
Lord_Tryzalot

user, isn't a stupid answer, try actually reading it

Supergrass
Supergrass

[math]
3y' + 6ty = 12 \\
3\dfrac{dy}{dt} + 6ty = 12 \\
y=4t \\
\dfrac{dy}{dt} = 4\\
t=0
[/math]

hairygrape
hairygrape

autism

Nojokur
Nojokur

so many retards...
At least this guy knows how to enter it into wolfram

Booteefool
Booteefool

Uh its already solved, tardcart

SomethingNew
SomethingNew

what is the function y(t) then, faggot

Spazyfool
Spazyfool

how the fuck do you get a 3 on that exam

Sir_Gallonhead
Sir_Gallonhead

Not him but our school accidentally gave us the bc instead of the ab. Still passed lul.

King_Martha
King_Martha

didn't even know sequences and series other than how to do a taylor expansion and got a 5 on the BC exam
it was definitely the easiest AP test i took

5mileys
5mileys

This is an embarrassing performance by all the anons posting before me.

In any case, here we have an inhomogeneous linear first order ODE. This would indicate that we should use an integrating factor. First, divide by 3:
y' + 2ty = 4
Then, we will try the integrating factor u(t) = e^(integral of 2t) = e^(t^2).
Multiplying through, we get
y'*e^(t^2) + y*2te^(t^2) = 4e^(t^2)
The left hand side is just
(y*e^(t^2))' = 4e^(t^2)
Now we integrate:
y*e^(t^2) + C = integral of 4e^(t^2) (which sadly has not got a closed form)
so if y is a solution, it must be of the form y = (C + integral of 4e^(t^2))*e^(-t^2)
Using initial conditions, C can be determined.
Then, you should plug the answer back in to show that y is indeed a solution (fuck doing that though).

PurpleCharger
PurpleCharger

isn't a stupid answer
second line is wrong

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